Volume Units lab

      Are the measurements cm^3 and mL the same thing. This project was proving rather cm^3 and mL are the same thing, or they are totally different from each other. I think that these two measurements are the same even though they show it in a different way.
      What this experiment consisted of was measuring the volume of six different shapes using cm^3 and mL. For cm^3 and mL to be the same thing one cm^3 had to equal on mL. The y-intercept had to equal zero, so this would be saying that 0 cm^3 =  0 mL. Which would make these two measurements the same. My group thought that cm^3 and mL were the same, but our data showed something different. Our linear equation said w=0.8142(mL/cm^3)m+11.93, but to show that the two measurements are the same the y-int. (11.93) had to be 0 because it would be saying that there is a shape that has measurement of 0 cm^3 and about 12 mL. Which this does not exist, so we might have had an error with calculating some of the numbers or somethings else may have happened. All the groups made graphs to show that the shapes showed that all the shapes were located around the fitted line. Showing that the two measurements are equal. As we talked as a class all the groups agreed that cm^3 and mL are the same thing. They're just written and calculated in different ways.
      Even thought our linear equation didn't fit the other groups; all the groups agreed that cm^3 and mL are the same. We are saying that cm^3 and mL are the same, but the data shows that they are similar. This is relevant because error plays a big part in collecting data. Which was probably one of the biggest reasons why they weren't exactly the same. Looking at everything that was talked about cm^3 and mL are the same thing even though they are measured in different ways. I think that this fits in with "How we view matter" and "How does matter behave" because we viewed why this experiment happened the way it did, but also how the experiment behaved with by the way that volume affected the two measurements.