Our equation was v=0.6535(mL/cm^3)V+16.17
Claim: 1mL=1cm^3
Evidence: Our slope is 16.17. To me that seems wrong, I believe there was some measuring errors, but the 5% rule showed that that is, in fact what our slope should be. The class average would have been rounded to 1, which indicates that for every cm^3, there should be a mL of water equal to it.

Reasoning: After looking at our graph and discussing others in class, it was obvious that we had made some sort of measuring error. Our graph shows that the rise and the run of each point are about the same each time, and in our data on the left the numbers are only within 2 or 3 numbers of each other, except for the last one, which was our mistake. That is why I think it is safe to say that 1mL=1cm^3.